2y^2+21y+10=

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Solution for 2y^2+21y+10= equation:


Simplifying
2y2 + 21y + 10 = 0

Reorder the terms:
10 + 21y + 2y2 = 0

Solving
10 + 21y + 2y2 = 0

Solving for variable 'y'.

Factor a trinomial.
(10 + y)(1 + 2y) = 0

Subproblem 1

Set the factor '(10 + y)' equal to zero and attempt to solve: Simplifying 10 + y = 0 Solving 10 + y = 0 Move all terms containing y to the left, all other terms to the right. Add '-10' to each side of the equation. 10 + -10 + y = 0 + -10 Combine like terms: 10 + -10 = 0 0 + y = 0 + -10 y = 0 + -10 Combine like terms: 0 + -10 = -10 y = -10 Simplifying y = -10

Subproblem 2

Set the factor '(1 + 2y)' equal to zero and attempt to solve: Simplifying 1 + 2y = 0 Solving 1 + 2y = 0 Move all terms containing y to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 2y = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 2y = 0 + -1 2y = 0 + -1 Combine like terms: 0 + -1 = -1 2y = -1 Divide each side by '2'. y = -0.5 Simplifying y = -0.5

Solution

y = {-10, -0.5}

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